1 In this example , i am going to show Spring Portlet Example

2 Environment:

Portal Server v6.1 ,Rad v7.5

Step3:

File>New> Select PortletProject>Project name(like AjaxSpringPortlet)>Choose the Target Runtime Server(like WebSphere Portal v6.1) and Portlet Type(Basic Portlet) like below

=>Click on Next >Next>Finish

Step 4: Project Structure like below

Step 5:

Create the folder in WEB-INF (like folder name is  jsp) like below

=>Click on > finish.

Step 6:

Then Select the jsp folder >Right click on > New>WebPage> Write the File Name like below

Click on > Finish

MainView.jsp like below

Code MainView.jsp:

<%@page

language=“java” contentType=“text/html; charset=ISO-8859-1”

pageEncoding=“ISO-8859-1” session=“false”%>

<%@ taglib uri=“http://java.sun.com/portlet_2_0&#8221; prefix=“portlet”%>

 

<%@taglib

uri=“http://www.ibm.com/xmlns/prod/websphere/portal/v6.1/portlet-client-model&#8221;

prefix=“portlet-client-model”%>

<%@taglib uri=“http://java.sun.com/portlet&#8221; prefix=“portletx”%>

<%@taglib uri=“http://www.ibm.com/xmlns/prod/websphere/portal/v6.1/portlet-client-model&#8221; prefix=“portlet-client-model” %>

 

<portlet-client-model:init>

<portlet-client-model:require module=“ibm.portal.xml.*” />

<portlet-client-model:require module=“ibm.portal.portlet.*” />

</portlet-client-model:init>

<portlet:defineObjects />

<portlet:resourceURL var=“getDetailsURL” id=“getDetailsURL”></portlet:resourceURL>

http://em

<h1 style=“color: red”>Hello Welcome To MainView </h1>

 

<div ng-app=“myApp” ng-controller=“myController”>

Enter user name: <input ng-model=“userName”><br>

<input type=“button” value=“Submit” ng-click=“getData()”><br>

<h3>{{message}}</h3>

 

var app = angular.module(‘myApp’, []);

app.controller(‘myController’, function($scope, $http) {

$scope.getData= function ()

{

var userName=$scope.userName;

alert(“user name is : “+userName);

$http.get(”,{ params: {user:userName}})

.then(function(response) {

alert(response);

$scope.message = response.data;

});

}

});

Step 7:

Create the class:

Right click on the project under  src >select the >class> and write the class name (like AjaxController.java)  like below

Click on> Finish

AjaxController.java like below

Code: AjaxController.java

 

package com.anu.controllers;

 

import java.io.IOException;

 

import javax.portlet.ResourceRequest;

import javax.portlet.ResourceResponse;

 

import org.springframework.stereotype.Controller;

import org.springframework.web.bind.annotation.RequestMapping;

import org.springframework.web.portlet.bind.annotation.RenderMapping;

import org.springframework.web.portlet.bind.annotation.ResourceMapping;

 

@Controller

@RequestMapping(“view”)

public class AjaxController {

@RenderMapping

public String showDefaultPage()

{

System.out.println(“inside showDefaultPage of AjaxController >>>> “);

String defautPage=”MainView”;

 

return defautPage;

}

 

@ResourceMapping(value =”getDetailsURL”)

public void getDetails(ResourceRequest req, ResourceResponse res) throws IOException

{

System.out.println(“inside getDetails >>>> AjaxSpring >>>  “);

String brideName=req.getParameter(“user”);

res.getWriter().write(“Hello Balu and “+brideName);

 

//String defautPage=”finalResults”;

 

//return defautPage;

System.out.println(“results sent >>>> “);

//return “Hello Welcome To New Angular Js World !!!!!”;

}

}

Step 8:

Create the (AjaxSpringPortlet-portlet.xml ) file like below

AjaxSpringPortlet-portlet.xml:

Code: AjaxSpringPortlet-portlet.xml like below

<?xml version=“1.0” encoding=“UTF-8”?>

<beans xmlns=“http://www.springframework.org/schema/beans&#8221;

xmlns:xsi=“http://www.w3.org/2001/XMLSchema-instance&#8221;

xmlns:p=“http://www.springframework.org/schema/p&#8221;

xmlns:context=“http://www.springframework.org/schema/context&#8221;

xsi:schemaLocation=“http://www.springframework.org/schema/beans 

http://www.springframework.org/schema/beans/spring-beans-3.0.xsd 

http://www.springframework.org/schema/context 

http://www.springframework.org/schema/context/spring-context-3.0.xsd&#8221;>

 

 

<bean id=“viewController” class=“com.anu.controllers.AjaxController”/>

 

<bean id=“portletModeHandlerMapping” class=“org.springframework.web.portlet.handler.PortletModeHandlerMapping”>

<property name=“defaultHandler” ref=“viewController”></property>

<property name=“portletModeMap”>

<map>

<entry key=“view”>

<ref bean=“viewController”/>

</entry>

</map>

</property>

</bean>

<bean id=“view” class=“org.springframework.web.servlet.view.InternalResourceViewResolver”>

<property name=“viewClass” value=“org.springframework.web.servlet.view.JstlView”/>

<property name=“prefix” value=“/WEB-INF/jsp/”/>

<property name=“suffix” value=“.jsp”/>

</bean>

 

</beans>

Step 10:

ApplicationContext.xml like below

Code ApplicationContext.xml   like below

<?xml version=“1.0” encoding=“UTF-8”?>

<beans

xmlns=“http://www.springframework.org/schema/beans&#8221;

xmlns:xsi=“http://www.w3.org/2001/XMLSchema-instance&#8221;

xmlns:p=“http://www.springframework.org/schema/p&#8221;

xsi:schemaLocation=“http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd&#8221;>

<!–<bean id=”view” class=”org.springframework.web.servlet.view.InternalResourceViewResolver”>

<property name=”viewClass” value=”org.springframework.web.servlet.view.JstlView”/>

<property name=”prefix” value=”/WEB-INF/jsp/”/>

<property name=”suffix” value=”.jsp“/>

</bean>

–>

</beans>

Step 11:

Web.xml like below

Code: web.xml :

<?xml version=“1.0” encoding=“UTF-8”?>

<web-app id=“WebApp_ID” version=“2.4” xmlns=“http://java.sun.com/xml/ns/j2ee&#8221; xmlns:xsi=“http://www.w3.org/2001/XMLSchema-instance&#8221; xsi:schemaLocation=“http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd&#8221;>

<display-name>AjaxSpringPortlet</display-name>

<servlet>

<servlet-name>ViewRendererServlet</servlet-name>

<servlet-class>org.springframework.web.servlet.ViewRendererServlet</servlet-class>

<load-on-startup>1</load-on-startup>

</servlet>

<servlet-mapping>

<servlet-name>ViewRendererServlet</servlet-name>

<url-pattern>/WEB-INF/servlet/view</url-pattern>

</servlet-mapping>

<listener>

<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>

</listener>

</web-app>

Step 12:

portlet.xml like below

Code: portlet.xml like below

<?xml version=“1.0” encoding=“UTF-8”?>

<portlet-app xmlns=“http://java.sun.com/xml/ns/portlet/portlet-app_2_0.xsd&#8221; version=“2.0” xmlns:xsi=“http://www.w3.org/2001/XMLSchema-instance&#8221; xsi:schemaLocation=“http://java.sun.com/xml/ns/portlet/portlet-app_2_0.xsd http://java.sun.com/xml/ns/portlet/portlet-app_2_0.xsd&#8221; id=“com.ibm.ajaxspringportlet.AjaxSpringPortlet.88f77076e5”>

<portlet>

<portlet-name>AjaxSpringPortlet</portlet-name>

<display-name xml:lang=“en”>AjaxSpringPortlet</display-name>

<display-name>AjaxSpringPortlet</display-name>

<portlet-class>org.springframework.web.portlet.DispatcherPortlet</portlet-class>

<init-param>

<name>wps.markup</name>

<value>html</value>

</init-param>

<expiration-cache>0</expiration-cache>

<supports>

<mime-type>text/html</mime-type>

<portlet-mode>view</portlet-mode>

</supports>

<supported-locale>en</supported-locale>

<resource-bundle>com.ibm.ajaxspringportlet.nl.AjaxSpringPortletResource</resource-bundle>

<portlet-info>

<title>AjaxSpringPortlet</title>

<short-title>AjaxSpringPortlet</short-title>

<keywords>AjaxSpringPortlet</keywords>

</portlet-info>

</portlet>

<default-namespace>http://AjaxSpringPortlet/</default-namespace&gt;

</portlet-app>

Step 12:

Result: 

 

 

 

 

 

 

 

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